Answer:
Still looking for the correct answer? The answer to the equation above is 15.
Let’s simplify the problem.
We will call cola ‘C’, burgers ‘B’, and fries ‘F’.
So, the equations we get are:
Equation 1: C + C + C = 30
Equation 2: C + B + B = 20
Equation 3: B + 2F + 2F = 9
Equation 4: B + F * C = ?
Let’s solve it.
Starting with Equation 1:
C + C + C = 30
3C = 30
C = 10
Replace the value of C in Equation 2:
C + B + B = 20
10 + 2B = 20
2B = 10
B = 5
Similarly, replace the value of B in Equation 3:
B + 2F + 2F = 9
5 + 4F = 9
4F = 4
F = 1
Now we know that one cola is 10, one burger is 5, and one pack of fries is 1.
Now, for the final Equation 4, replace all values:
B + F * C = ?
5 + 1 * 10 = ?
Applying BODMAS (Order of operations):
5 + 10 = 15
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